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Thesis: WuotD after bussum.science.ru.nl crashed on me
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@ -23,11 +23,12 @@
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% phase variables
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% phase variables
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\newcommand{\pTrue}{\phi}
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\newcommand{\pTrue}{\phi}
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\newcommand{\PTrue}{\Phi}
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\newcommand{\pMeas}{\varphi}
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\newcommand{\pMeas}{\varphi}
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\newcommand{\pTrueEmit}{\pTrue_0}
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\newcommand{\pTrueEmit}{\pTrue_0}
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\newcommand{\pTrueArriv}{\pTrueArriv'}
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\newcommand{\pTrueArriv}{\pTrueArriv'}
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\newcommand{\pMeasArriv}{\pMeas}
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\newcommand{\pMeasArriv}{\pMeas_0}
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\newcommand{\pProp}{\pTrue_d}
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\newcommand{\pProp}{\pTrue_d}
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\newcommand{\pClock}{\pTrue_c}
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\newcommand{\pClock}{\pTrue_c}
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@ -132,16 +133,16 @@ Combining \eqref{eq:interantenna_t0} and \eqref{eq:transmitter2antenna_t0} then
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\label{eq:synchro_mismatch_clocks}
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\label{eq:synchro_mismatch_clocks}
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\phantom{.}
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\phantom{.}
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\begin{aligned}
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\begin{aligned}
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\Delta (\tClock)_{ij}
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(\Delta \tClock)_{ij}
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&\equiv (\tClock)_i - (\tClock)_j \\
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&\equiv (\tClock)_i - (\tClock)_j \\
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&= \left[ (\tMeasArriv)_i - (\tTrueArriv)_i \right] - \left[ (\tMeasArriv)_j - (\tTrueArriv)_j \right] \\
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&= \left[ (\tMeasArriv)_i - (\tTrueArriv)_i \right] - \left[ (\tMeasArriv)_j - (\tTrueArriv)_j \right] \\
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&= \left[ (\tMeasArriv)_i - (\tMeasArriv)_j \right] - \left[ (\tTrueArriv)_i - (\tTrueArriv)_j \right] \\
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&= \left[ (\tMeasArriv)_i - (\tMeasArriv)_j \right] - \left[ (\tTrueArriv)_i - (\tTrueArriv)_j \right] \\
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&= \Delta (\tMeasArriv)_{ij} - \Delta (\tTrueArriv)_{ij} \\
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&= (\Delta \tMeasArriv)_{ij} - (\Delta \tTrueArriv)_{ij} \\
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&= \Delta (\tMeasArriv)_{ij} - \Delta (\tProp)_{ij} \\
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&= (\Delta \tMeasArriv)_{ij} - (\Delta \tProp)_{ij} \\
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\end{aligned}
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\end{aligned}
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.
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.
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\end{equation}
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\end{equation}
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Thus, measuring $(\tMeasArriv)_i$ and determining $(\tProp)_i$ provides the synchronisation mismatch between the antennas.
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Thus, measuring $(\tMeasArriv)_i$ and determining $(\tProp)_i$ for two antennas provides the synchronisation mismatch between them.
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\\
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\\
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% is relative
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% is relative
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@ -239,24 +240,25 @@ The $\tTrueEmit$ term describing the transmitter time in \eqref{eq:transmitter2a
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\tTrueEmit = \left[ \frac{\pTrueEmit}{2\pi} + k\right] T
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\tTrueEmit = \left[ \frac{\pTrueEmit}{2\pi} + k\right] T
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,
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,
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\end{equation}
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\end{equation}
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with $\pTrueEmit$ the phase of the beacon at time $\tTrueEmit$, $T$ the period of the beacon and $k \in \mathbb{Z}$ unknown.
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with $-\pi < \pTrueEmit < \pi$ the phase of the beacon at time $\tTrueEmit$, $T$ the period of the beacon and $k \in \mathbb{Z}$.
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\\
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\\
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This changes the synchronisation mismatches in \eqref{eq:synchro_mismatch_clocks} to
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This affects \eqref{eq:transmitter2antenna_t0}, thus changing the synchronisation mismatches in \eqref{eq:synchro_mismatch_clocks} to
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\begin{equation}
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\begin{equation}
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\label{eq:synchro_mismatch_clocks_periodic}
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\label{eq:synchro_mismatch_clocks_periodic}
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\phantom{.}
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\phantom{.}
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\begin{aligned}
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\begin{aligned}
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\Delta (\tClock)_{ij}
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(\Delta \tClock)_{ij}
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&\equiv (\tClock)_i - (\tClock)_j \\
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&\equiv (\tClock)_i - (\tClock)_j \\
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&= \Delta (\tMeasArriv)_{ij} - \Delta (\tTrueArriv)_{ij} \\
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&= (\Delta \tMeasArriv)_{ij} - (\Delta \tTrueArriv)_{ij} \\
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&= \Delta (\tMeasArriv)_{ij} - \Delta (\tProp)_{ij} + \Delta k_{ij} T\\
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&= (\Delta \tMeasArriv)_{ij} - (\Delta \tProp)_{ij} - \Delta k_{ij} T\\
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&= \left[ \frac{ (\Delta \pMeasArriv)_{ij}}{2\pi} - \frac{(\Delta \pProp)_{ij} }{2\pi} - \Delta k_{ij} \right] T\\
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&\equiv \left[ \frac{ (\Delta \pClock)_{ij} }{2\pi} - \Delta k_{ij} \right] T\\
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\end{aligned}
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\end{aligned}
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.
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.
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\end{equation}
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\end{equation}
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% lifting period multiplicity -> long timescale
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% lifting period multiplicity -> long timescale
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Synchronisation is possible with the caveat of being off by an integer amount $\Delta k_{ij}$ of periods.
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Synchronisation is possible with the caveat of being off by an unknown integer amount of periods $\Delta k_{ij}$.
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In phase-locked systems this is called syntonisation.
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In phase-locked systems this is called syntonisation.
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There are two ways to lift this period degeneracy.
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There are two ways to lift this period degeneracy.
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\\
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\\
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@ -291,16 +293,156 @@ Later, a mechanism to lift the period degeneracy using an airshower as discrete
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%%
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%%
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%% Phase measurement
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%% Phase measurement
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\subsection{Phase measurement}
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\subsection{Phase measurement}
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A continuous beacon can syntonise antennas by correcting for the measured difference in beacon phase $(\Delta \pMeasArriv)_{ij}$.
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The beacon phase can be derived from an antenna trace by applying a Fourier Transform to the data.
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\\
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The trace will contain noise from various sources external and internal to the detector such as
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\begin{figure}[h]
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\begin{subfigure}{0.45\textwidth}
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\includegraphics[width=\textwidth]{beacon/sine_beacon.pdf}
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\caption{
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A waveform of a strong sine wave with gaussian noise.\Todo{Add noise}
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}
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\label{fig:beacon:sine}
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\end{subfigure}
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\hfill
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\begin{subfigure}{0.45\textwidth}
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\includegraphics[width=\textwidth]{fourier/noisy_sine.pdf}
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\caption{
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Fourier Spectrum of the signals.
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\Todo{Add fourier spectra?}
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}
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\label{fig:beacon:spectrum}
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\end{subfigure}
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\\
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\begin{subfigure}{0.45\textwidth}
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\includegraphics[width=\textwidth]{beacon/ttl_beacon.pdf}
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\caption{
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TTL
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}
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\label{fig:beacon:ttl}
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\end{subfigure}
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\caption{
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Both show two samplings with a small offset in time.
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Reconstructing the signal is easier to do for the sine wave with the same samplelength and number of samples.
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}
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\label{fig:beacon:ttl_sine_beacon}
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\end{figure}
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% DTFT
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% DTFT
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\subsubsection{Discrete Time Fourier Transform}
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\subsubsection{Discrete Time Fourier Transform}
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\begin{equation}
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\label{eq:fourier}
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X(\omega) = \frac{1}{2\pi} \int \dif{t}\, x(t)\, e^{i \omega t}
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\end{equation}
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\begin{equation}
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\label{eq:fourier:dtft}
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X(\omega) = \frac{1}{2\pi N} \sum_{n=0}^N x(t[n])\, e^{i \omega t[n]}
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\end{equation}
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\begin{equation}
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\label{eq:fourier:dft}
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X_k = \frac{1}{N} \sum_{n=0}^{N-1} x[n]\, \cdot e^{ \frac{i 2 \pi}{N} k n }
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\end{equation}
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with $\omega = \tfrac{k}{N}$.
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% Signal to noise
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% Signal to noise
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\subsubsection{Signal to Noise}
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\subsubsection{Signal to Noise}
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Phasor concept
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\cite{goodman1985:2.9}
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Known phasor $\vec{s}$ + random phasor $\vec{m} = a e^{i\pTrue}$ with $-\pi < \pTrue < \pi$ and $a \geq 0$.
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\begin{equation}
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\label{eq:phasor_pdf}
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p_{A\PTrue}(a, \pTrue; s, \sigma)
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= \frac{a}{2\pi\sigma^2}
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\exp[ -
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\frac{
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{\left( a \cos \pTrue - s \right)}^2
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+ {\left( a \sin \pTrue \right)}^2
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}{
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2 \sigma^2
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}
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]
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\end{equation}
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requiring $ -\pi < 0 \leq pi $ and $a > 0$, otherwise $p_{A\PTrue} = 0$.
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\bigskip
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Rician distribution ( 2D Gaussian at $\nu$ with $\sigma$ spread)
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\begin{equation}
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\label{eq:amplitude_pdf:rice}
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p^{\mathrm{RICE}}_A(a; s, \sigma)
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= \frac{a}{\sigma^2}
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\exp[-\frac{a^2 + s^2}{2\sigma^2}]
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\;
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I_0\left( \frac{a s}{\sigma^2} \right)
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\end{equation}
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with $I_0(z)$ the modified Bessel function of the first kind with order zero.
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No signal $\mapsto$ Rayleigh ($s = 0$);
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Large signal $\mapsto$ Gaussian ($s \gg a$)
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\bigskip
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Rayleigh distribution
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\begin{equation}
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\label{eq:amplitude_pdf:rayleigh}
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p_A(a; s=0, \sigma)
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= p^{\mathrm{RICE}}_A(a; \nu = 0, \sigma)
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= \frac{a}{\sigma^2} e^{-\frac{a^2}{2\sigma^2}}
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\end{equation}
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with $\sigma = \frac{\mu_1}{\sqrt{\frac{\pi}{2}}}$ and $\mu_2 = \frac{ 4 - \pi }{2}\sigma^2$.
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\bigskip
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Gaussian distribution
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\begin{equation}
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\label{eq:amplitude_pdf:gauss}
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p_A(a; \sigma) = \frac{1}{\sqrt{2\pi}} \exp[-\frac{{\left(a + s\right)}^2}{2\sigma^2}]
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\end{equation}
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\bigskip
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Rician phase distribution: uniform (low $s$) + gaussian (high $s$)
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\begin{equation}
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\label{eq:phase_pdf:full}
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p_\PTrue(\pTrue; s, \sigma) =
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\frac{ e^{-\left(\frac{s^2}{2\sigma^2}\right)} }{ 2 \pi }
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+
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\sqrt{\frac{1}{2\pi}}
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\frac{s}{\sigma}
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e^{-\left( \frac{s^2}{2\sigma^2}\sin^2{\pTrue} \right)}
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\frac{\left(
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1 + \erf{ \frac{s \cos{\pTrue}}{\sqrt{2} \sigma }}
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\right)}{2}
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\cos{\pTrue}
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\end{equation}
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with
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\begin{equation}
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\label{eq:erf}
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\erf{\left(z\right)} = \frac{2}{\sqrt{\pi}} \int_0^z \dif{t} e^{-t^2}
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\end{equation}
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.
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\bigskip
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Phase distribution: gaussian
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\begin{equation}
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\label{eq:phase_pdf:gaussian}
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p_\PTrue(\pTrue; s, \sigma) = \frac{1}{\sqrt{2} \sigma} \exp\left(- \frac{s^2}{2\sigma^2} \right)
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\end{equation}
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\begin{figure}
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\includegraphics[width=0.5\textwidth]{beacon/time_res_vs_snr.pdf}
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\caption{Measured Time residuals vs Signal to Noise ration}
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\label{fig:time_res_vs_snr}
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\end{figure}
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\subsection{Period degeneracy}
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\subsection{Period degeneracy}
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% period multiplicity/degeneracy
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% period multiplicity/degeneracy
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@ -478,69 +620,6 @@ However, while in a static setup the value of $k$ can be estimated from the dist
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\\
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\\
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\hrule
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\bigskip
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\hrule
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\section{Impulsive Beacon}
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\subsection{Properties}
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\section{Sine Beacon}
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\subsection{Fourier Transform}
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\begin{equation}
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\label{eq:fourier}
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\hat{f}(\omega) = \frac{1}{2\pi} \int \dif{t}\, f(t)\, \exp(i \omega t)
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\end{equation}
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\begin{equation}
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\label{eq:fourier:discrete_time}
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\end{equation}
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\subsection{Properties}
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Phasor concept
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Known phasor $\vec{s}$ + random phasor $\vec{m} = a e^{i\theta}$ with $-\pi < \theta < \pi$ and $a > 0$.
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\subsubsection{Amplitude distribution}
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\begin{equation}
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\label{eq:amplitude_pdf:rayleigh}
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p_A(a) = \frac{a}{\sigma^2} \exp(-\frac{a^2}{2\sigma^2})
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\end{equation}
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\subsubsection{Phase distribution}
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\begin{equation}
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\label{eq:phase_pdf:full}
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p_\Theta(\theta) =
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\frac{ e^{-\left(\frac{s^2}{2\sigma^2}\right)} }{ 2 \pi }
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+
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\sqrt{\frac{1}{2\pi}}
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\frac{s}{\sigma}
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e^{-\left( \frac{s^2}{2\sigma^2}\sin^2{\theta} \right)}
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\frac{\left(
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1 + \erf{ \frac{s \cos{\theta}}{\sqrt{2} \sigma }}
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\right)}{2}
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\cos{\theta}
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\end{equation}
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with
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\begin{equation}
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\label{eq:erf}
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\erf{\left(z\right)} = \frac{2}{\sqrt{\pi}} \int_0^z \dif{t} e^{-t^2}
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\end{equation}
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.
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\begin{equation}
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\label{eq:phase_pdf:gaussian}
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\end{equation}
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\begin{figure}
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\includegraphics[width=0.5\textwidth]{beacon/time_res_vs_snr.pdf}
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\caption{Measured Time residuals vs Signal to Noise ration}
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\label{fig:time_res_vs_snr}
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\end{figure}
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\subsection{Lifting period degeneracy}
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\subsection{Lifting period degeneracy}
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\begin{figure}
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\begin{figure}
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\begin{subfigure}[t]{0.5\textwidth}
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\begin{subfigure}[t]{0.5\textwidth}
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